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A particle of mass m is lying on smooth ...

A particle of mass m is lying on smooth horizontal table. A constant force F tangential to the surface is applied on it. Find .
(a) average power over a time interval from `t=0` to `t=t,`
(b) instantaneous power as function of time t.

Text Solution

Verified by Experts

The correct Answer is:
B
(a) `a=F/m="constant"`
`v=at=F/m t rArr P_(av)=W/t=(1/2mv^2)/t=((1/2)(m)((Ft)/m)^(2))/(t)`
`=(F^(2)t)/2_(m)`
(b)`P^(i)=Fvcos 0^@=Fv=(F) ((F ^(2)t)/(m))`
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