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A block is constrained to move along x-a...

A block is constrained to move along x-axis under a forc `F=4/(x^(2))(xne0)`. Here, F is in newton and x in metre. Find the work done by this force when the block is displaced from `x=4` m to `x=2m`.

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The correct Answer is:
A
`W = int_(4)^(2)Fdx = int_(4)^(2)(4)/(x^(2))dx`
`= -4[(1)/(x)]_(4)^(2) = -4[(1)/(2) - (1)/(4)] = -1J`
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