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Find the speed of both the blocks at the...

Find the speed of both the blocks at the moment the block `m_(2)` hits the wall AB, after the blocks are released from rest. Given that `m_(1) =0.5 kg` and `m_(2) =2 kg, (g=10 m//s^(2))`
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Text Solution

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The correct Answer is:
A, B, C
From conservation of energy ,
`m_(2)gh_(2)=m_(1)gh+(1) +1/2m_(1)v_(1)_(2) + 1/2 m_(2)v(1)^(2)`
Here, `v_(1)=v^(2) cos theta`
:. `2xx10xx1=(0.5)(10)(sqrt5-1)+1/2xx0.5`
`xv_(2)^(2)xx((2)/sqrt(5))^(2) +1/2xx2xxv_(2)^(2)`
`:. 20 =6.18+0.2 v_2^(2)+v_(2)^(2)`

`v^(2) =3.39 m//s`
and `v_(1) =v^(2) cos theta =2/sqrt(5)xx3.39`
or `v_(1) =3.03m//s`,
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