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A small particle of mass m attached with...

A small particle of mass `m` attached with a light inextensible thread of length `L` is moving in a verical circle. In the given case particle is moving in complete vertical circle and ratio of its maximum to minimum velocity is `2:1` .
Minimum velocity of the particle is

A

`4sqrt((gL)/(3))`

B

`2sqrt((gL)/(3))`

C

`sqrt((gL)/(3))`

D

`3sqrt((gL)/(3))`

Text Solution

Verified by Experts

The correct Answer is:
B
Maximum velocity is at bottommost point and minimum velocity is at tomost point.
`sqrt(u_(min)^(2)+2g(2L))/(u_(min))=(2)/(1)`
On solving, we get
`u_(min)=2sqrt((gL)/(3))`
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