Home
Class 11
PHYSICS
The net force versus time graph of a roc...

The net force versus time graph of a rocket is shown in figure The mass of the rocket is `1200kg`. Calculate velocity of rocket, 16 seconds after starting from rest. Neglect gravity.

Text Solution

Verified by Experts

The correct Answer is:
B
Impulse=area under `F-t` graph
`=Deltap=m(v_f-v_i)`
`:. v_f=(Area)/(m)` (as `v_i=0`)
`=1/2xx((20xx10^3)(8+16))/(12000)`
`=200m//s`
Promotional Banner

Topper's Solved these Questions

  • CENTRE OF MASS, LINEAR MOMENTUM AND COLLISION

    DC PANDEY|Exercise Exercise 11.6|11 Videos

  • CENTRE OF MASS, LINEAR MOMENTUM AND COLLISION

    DC PANDEY|Exercise Level 1 Assertion and Reason|15 Videos

  • CENTRE OF MASS, LINEAR MOMENTUM AND COLLISION

    DC PANDEY|Exercise Exercise 11.4|4 Videos

  • CENTRE OF MASS, IMPULSE AND MOMENTUM

    DC PANDEY|Exercise Comprehension type questions|15 Videos

  • CIRCULAR MOTION

    DC PANDEY|Exercise Medical entrances s gallery|19 Videos

Similar Questions

Explore conceptually related problems

The velocity time graph of a linear motion is shown in the figure. The distance from the starting point after 8 seconds will be .

A rocket is fired upwards. Its velocity versus time graph is shown in the figure-1.131. The maximum height reached by the rocket is:

If the maximum possible exhaust velocity of a rocket be 2km//s calculate the ratio m_(0)//m for it to acquire a veocity of 11.2km//s after starting from rest .

A rocket motor consumes 100 kg of fuel per second exhausting it with a speed of 6 xx 10^(3) ms^(-1) What thrust is exerted on the rocket ? What will be the velocity of the rocket at the instant its mass is reduced to (1 // 40) of its initial mass ? Take initial velocity of rocket as zero . Neglect gravity .

In a rocket, fuel burns at the rate of 2 kg/s. This fuel gets ejected from the rocket with a velocity of 80 km/s. Force exerted on the rocket is -

For a Rocket propulsion velocity of exhaust gases relative to rocket is 2km/s. If mass of rocket system is 1000 kg, then the rate of fuel consumption for a rockt to rise up with acceleration 4.9 m//s^(2) will be:-

The velocity v of mass m of a rocket at time t is given by the equation : m (dv)/(dt)+V (dm)/(dt)=0 , where 'V' is the constant velocity of emission. If the rocket starts from rest when t=0 with mass m, prove that : v= V log ((m_(0))/(m)) .

Calculate the ratio m_(0)//m for a rocket to attain the escape velocity of 11.2km s^(-1) after starting from rest, when maximum exhaust velocity of gases is 1.6km//s .