Find the moment of inertia of a solid sphere of mass `M` and radias `R` about an axis XX shown in figure.
A
`(7)/(5)MR^(2)`
B
`(4)/(5)MR^(2)`
C
`(3)/(5)MR^(2)`
D
`(2)/(5)MR^(2)`
Text Solution
Verified by Experts
The correct Answer is:
A
From theorem of parallel axis `I_(XX)=I_(COM)+Mr^(2)=(2)/(5)MR^(2)+MR^(2)` `=(7)/(5)MR^(2)` Radius of gyration `K=sqrt((I)/(M))=sqrt(((7)/(5)MR^(2))/(M))=sqrt((7)/(5))R`
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