A rod of mass 2 kg ad length 2 m is rotating about its one end `O` wth an angular velocity `omega=4rad//s`. Find angular momentum of the rod about the axis rotation.
Text Solution
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In pure rotational motion of a rigid body, component of total angualr momentum about axis of rotation is given by `L=Iomega=((ml^(2))/(3))omega` `(I_(0)=(ml^(3))/(3))` Substituting the value we have, `L=((2)(2)^(2))/(3)(4)` `=(32)/(3)kg-m^(2)//s` direction of this component is perperdicular to paper inwards (from right hand rule), as the rotation clockwise.
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