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In the figure shown upsilon=2m//s omega=...


In the figure shown `upsilon=2m//s` `omega=5rad//s` and `CP=1m`
In terms of `hati` and `hatj` find linear velocity of particle P.

Text Solution

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For particle `P`,
`r=CP=1m`
`impliesromega=(1)(5)=5m//s`
Net velocity of `P` is the vector sum of v and `romega` as shown in figure.
`thereforeV_(P)=2hati+(5cos53^(@)hati-5sin53hatj)`
`=2hati+3hati-4hatj=(5hati-4hatj)m//s`
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