A solid disc is rolling without slipping on a horizontal ground as shown in figure. Its total kinetic energy is 100 J. what is its translational and rotational kinetic energy?
Text Solution
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In case of pure rooilling ratio of rational kinetic energy and tranlational kinetic energy is `(1)/(2)` or `(K_(R))/(K_(T))=(1)/(2)impliesthereforeK_(R)=((1)/(1+2))` (total kinetic energy) `=(1)/(3)(100J)=(100)/(3)J` Similarly `K_(T)=((2)/(1+2))` (total kintic energy ) `=(2)/(3)(100J)=(200)/(3)J`
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