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A particle of mass m=1kg is projected wi...

A particle of mass `m=1kg` is projected with speed `u=20sqrt(2)m//s` at angle `theta=45^(@)` with horizontal find the torque of the weight of the particle about the point of projection when the particle is at the highest point.

Text Solution

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`tau=(mgR)/(2)=((mg)u^(2)sin2theta)/(2g)`
`=(mu^(2))/(2)` (as `theta=45^(@)`)
`=((1)(20sqrt(2))^(2))/(2)`
`=400N-m`
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