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Moment of inertia of a thin semicircular...

Moment of inertia of a thin semicircular disc `(mass - M & radius = R)` about an axis through point `O` and perpendicular to plane of disc, is given by :
.

A

`Mr^(2)`

B

`(1)/(2)Mr^(2)`

C

`(1)/(4)Mr^(2)`

D

`(2)/(5)Mr^(2)`

Text Solution

Verified by Experts

`I_("whole disc")=(1)/(2)(2M)r^(2)=Mr^(2)`
`thereforeI_("half disc")=(1)/(2)Mr^(2)`
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