If `R` is the radius of gyration of a body of mass `M` and radius `r`, then the ratio of its rotational to translational kinetic energy in the rolling condition is

Options

A. `(R^(2))/(R_(2)+r^(2))`
B. `(R^(2))/(r^(2))`
C. `(r^(2))/(R^(2))`
D. `1`

Explanation

`(K_(R))/(K_(T))=((1)/(2)Iomega^(2))/((1)/(2)mv^(2))=(Iomega^(2))/(mv^(2))`
`=((mR^(2))(v//r)^(2))/(mv^(2))=(R^(2))/(r^(2))`