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Two identical discs are positioned on a vertical axis as shown in the figure. The bottom disc is rotating at angular velocity `omega_(0)` and has rotational kinetic energy `K_(0)`. Change in the rotational kinetic energy of the system is

A

`K_(0)//2`

B

`-K_(0)//2`

C

`-K_(0)//4`

D

`K_(0)//4`

Text Solution

Verified by Experts

The correct Answer is:
A

`K=(L^(2))/(2I)` or `Kprop(1)/(I)` As `I` has doubled, so `K` will become half.
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