A wheel rotates around a stationary axis so that the rotation angle `theta` varies with time as `theta=at^(2)` where `a=0.2rad//s^(2)`. Find the magnitude of net acceleration of the point A at the rim at the moment `t=2.5s` if the linear velocity of the point A at this moment is `v=0.65m//s`.

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Find the angular velocity (ω)
Given the angular displacement \(\theta = at^2\), we can find the angular velocity \(\omega\) by differentiating \(\theta\) with respect to time \(t\):

\[ \omega = \frac{d\theta}{dt} = \frac{d(at^2)}{dt} = 2at \]
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