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A solid body rotates about a stationary ...

A solid body rotates about a stationary axis so that the rotation angle `theta` varies with time as `theta=6t-2t^(3)` radian. Find
(a) the angular acceleration at the moment when the body stops and
(b) the average value of angular velocity and angular acceleration averaged over the time interval between `t=0` and the complete stop.

Text Solution

Verified by Experts

`theta=6t-2t^(3)`
`omega=(dtheta)/(dt)`
`=6-6t^(2)`
`alphal=(domega)/(dt)=-12t`
`omega=0`
at `t=1` sec
`(omega)_(0-1)=((int_(0)^(1)omegadt)/(1))=int_(0)^(1)(6-6t^(2))dt`
`(alpha)_(0-1)=((int_(0)^(1))alphadt)/(1)=int_(0)^(1)(-12t)`
`=-6rad//s^(2)`
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