A thin unifrom rod of mass `m` and length `l` is free to rotate about its upper end When it is at rest. It receives an impulse `J` as its lowest point, normal to its length immediately after impact.

Options

A. the angular mumentum of the rod is Jl
B. The angular velocity of the rod is `3J//ml`
C. The kinetic energy of the rod is `3J^(2)//2m`
D. All of these

Explanation

Angular momentum `=` Angular impulse
or `Iomega=Jl`
or `omega=("angular impulse")/(I)`
`=(Jl)/(ml^(2)//3)=(3J)/(ml)`
`KE=(1)/(2)Iomega^(2)=(1)/(2)((ml)/(3))^(2)((3J)/(ml))^(2)`
`=(3J^(2))/(2m)`