Due to slippoing points A and B on the rim of the disk have the velocities shown. Determine the velocities of the centre point C and point F at this instant.

Explanation

`v+Romega=1.5`
and `Romega-v=3.0`
From Eq. (i) and (ii) we have
`Romega=2.25m//s` and `v=-0.75m//s`
thus velocity of point C is 0.75 `m//s` (towards left).
`V_(F)=sqrt(v^(2)+(Romega)^(2)+2v(Romega)cos(90+30))`
`=sqrt(0.5625+5.0625+2xx0.75xx2.25xx(-(1)/(2)))`
`1.98m//s`