Home
Class 11
PHYSICS
F-x equation of a body in SHM is F + 4...

`F-x` equation of a body in SHM is
`F + 4x=0`
Here, `F` is in newton and `x` in meter. Mass of the body is `1 kg`. Find time period of oscillations.

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
The given equation can be written as
`F = -4x`
Comparing this eqution with the standard equation of SHM or
`F = -Kx`
we get `K=4N//m`
Now, `T=2pi sqrt((m)/(k))`
`=2pi sqrt((1)/(4)) = (pi)s`
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    DC PANDEY|Exercise Example Type 1|1 Videos

  • SIMPLE HARMONIC MOTION

    DC PANDEY|Exercise Example Type 2|1 Videos

  • SEMICONDUCTORS AND ELECTRONIC DEVICES

    DC PANDEY|Exercise More than One Option is Correct|3 Videos

  • SOLVD PAPERS 2017 NEET, AIIMS & JIPMER

    DC PANDEY|Exercise Solved paper 2018(JIPMER)|38 Videos

Similar Questions

Explore conceptually related problems

F - x equation of a body of mass 2kg in SHM is F + 8x = 0 Here, F is in newton and x in meter.Find time period of oscillations.

a - x equation of a body in SHM is a + 16 x = 0 . Here, x is in cm and a in cm//s^(2) . Find time period of oscillations.

a - x equation of a particle in SHM is a + 4x = 0 Here, a is in cm//s^(2) and x in cm.Find time period in second.

The equation of motion of a particle in SHM is a +4x = 0 . Here 'a' is linear acceleration of the particle at displacement 'x' in metre. Its time period is

A force F=(10+0.50x) acts on a particle in the x direction, where F is in newton and x in meter./find the work done by this force during a displacement form x=0 tox=2.0m

The position (x) of body moving along x-axis at time (t) is given by x=3f^(2) where x is in matre and t is in second. If mass of body is 2 kg, then find the instantaneous power delivered to body by force acting on it at t=4 s.

For SHM to take place force acting on the body should be proportional to -x or F =- kx . If A be the amplitude then energy of oscillation is 1//2KA^(2) . Force acting on a block is F = (-4x +8) . Here F is in newton and x in the position of block on x-axis in meters

A force given by the relation F = 8t, (F in Newton and t in sec.) acts on a body of mass 2kg. Initially at rest. Choose the correct option.

A particle of mass 0.1kg executes SHM under a force F =- 10x (N) . Speed of particle at mean position is 6 m//s . Find its amplitude of oscillation.

A force F = - 10x + 2 acts on a particle of mass 0.1 kg where x is in m and F in newton. If is released from rest at x = 0 , find: a. Amplitude: b. Time period: c. Equation of motion.