A `0.5 kg` body performs simple harmonic motion with a frequency of `2 Hz` and an amplitude of `8 mm`. Find the maximum velocity of the body, its maximum acceleration and the maximum restoring force to which the body is subjected.

Answer

A, B, C, D

Explanation

`v_(max) = omega A = 2pifA`
`= (2pi)(2)(8 xx 10^(-3))`
`= 0.101 m//s`
`a_(max) = omega^(2)A = (2pi f)^(2) A`
`= 4 xx pi^(2) xx 4 xx 8 xx 10^(-3)`
`= 1.264m//s^(2)`
` F_(max) = ma_(max)`
`= (0.5)(1.264)`
`= 0.632 N`