Home
Class 11
PHYSICS
A particle executes simple harmonic moti...

A particle executes simple harmonic motion of amplitude `A` along the x - axis. At `t = 0`, the position of the particle is `x = (A)/(2)` and it moves along the positive x - direction. Find the phase contant `delta`, if of the equation is written as `x = Asin (omega t + delta)`.

Text Solution

Verified by Experts


`x = A sin (omega t + 30^(@))`
`:. delta = 30^(@)`.
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    DC PANDEY|Exercise Exercise 14.3|7 Videos
  • SIMPLE HARMONIC MOTION

    DC PANDEY|Exercise Exercise 14.4|4 Videos
  • SIMPLE HARMONIC MOTION

    DC PANDEY|Exercise Intro. Exer.|1 Videos
  • SEMICONDUCTORS AND ELECTRONIC DEVICES

    DC PANDEY|Exercise More than One Option is Correct|3 Videos
  • SOLVD PAPERS 2017 NEET, AIIMS & JIPMER

    DC PANDEY|Exercise Solved paper 2018(JIPMER)|38 Videos

Similar Questions

Explore conceptually related problems

A particle executes simple harmonic motion of mplitude A along the X-axis. At t=0 the position of the particle is x=A/2 and it moves along the positive x-direction. Find the phase constante delta if the equation is written as x=Asin(omegat+delta)

A particle executes SHMx=Asin(omegat+phi) . At t=0 , the position of the particle is x=(sqrt3A)/(2) and it moves along the positive x-direction. Find (a) phase constant phi (b) velocity at t=pi/omega (c) acceleration at t=pi/omega

A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential Energy (PE) equals kinetic energy (KE), the position of the particle will be :

The displacement-time equation of a particle executing SHM is A-Asin(omegat+phi) . At tme t=0 position of the particle is x= A/2 and it is moving along negative x-direction. Then the angle phi can be

A particle is executing simple harmonic motion with an amplitude A and time period T. The displacement of the particles after 2T period from its initial position is

Position of particle moving along x-axis is given by x=2t^(3)-4t+3 Initial position of the particle is

A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude.

The displecemen-time equation of a particle execitting SHM is x = A sin (omega t + phi) At time t = 0 position of are position is x = A//2 and it is moving along negative x- direction .Then the angle phi can be

A particle executes simple harmonic motion with an amplitude of 10 cm and time period 6 s . At t = 0 it is position x = 5 cm from mean postion and going towards positive x- direaction. Write the equation for the displacement x at time L . Find the magnitude of the acceleration of the particle at t = 4 s .

The position of particle moving along the x-axis veries with time t as x=6t-t^(2)+4 . Find the time-interval during which the particle is moving along the positive x-direction.