Home
Class 11
PHYSICS
A bob of mass 10 kg is attached to a wir...

A bob of mass `10 kg` is attached to a wire `0.3 m` long. Its breaking stress is `4.8xx10^(7) N//m^(2)`. Then area of cross-section of the wire is `10^(-6) m^(2)`. What is the maximum angular velocity with which it can be rotated in a horizontal circle?

A

`8 rad//s`

B

`4 rad//s`

C

`2 rad//s`

D

`1rad//s`

Text Solution

Verified by Experts

The correct Answer is:
B
`T =mlomega^(2)`
` T/A = sigma_(max) = (mlomega^(2))/A`
:. ` omega = sqrt((sigma_(max)A)/(ml)`
`=sqrt((4.8xx10^(7)xx10^(-6))/(10xx10.3)`
`= 4 rad//s`
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY

    DC PANDEY|Exercise Level 2 More Than One Correct|8 Videos

  • ELASTICITY

    DC PANDEY|Exercise Level 2 Comprehension Based|6 Videos

  • ELASTICITY

    DC PANDEY|Exercise Level 1 Subjective|8 Videos

  • CURRENT ELECTRICITY

    DC PANDEY|Exercise All Questions|434 Videos

  • ELECTROSTATICS

    DC PANDEY|Exercise Integer|17 Videos

Similar Questions

Explore conceptually related problems

A body of mass 10 kg is attached to a wire 0.3 m long. Its breaking stress is 4.8xx10^(7)N//m^(2). The area of cross-section of wire is 10^(-6)m^(2). What is the maximum angular velocity with which it can be rotated in a horizontal circle?

A bob of mass 10 kg is attached to wire 0.3 m long. Its breaking stress is 4.8 xx 10^(7) N//m^(2) . The area of cross section of the wire is 10^(-6) m^(2) . The maximum angular velocity with which it can be rotated in a horizontal circle

A small but heavy block of mass 10 kg is attached to a wire 0.3 m long. Its breaking stress is 4.8 xx 10^(7) N//m^(2) . The area of the cross section of the wire is 10^(-6) m^(2) . The maximum angular velocity with which the block can be rotated in the horizontal circle is

A body of mass 500 g is fastened to one end of a steel wire of length 2m and area of cross-section 2m m^(2) . If the breaking stress of the wire is 1.25 xx 10^(7) N//m^(2) , then the maximum angular velocity with which the body can be rotated in a horizontal circle is

The breaking stress of steel is 7.85 xx 10^(8) N//m^(2) and density of steel is 7.7 xx 10^(3) kg//m^(3) . The maximum frequency to which a string 1 m long can be tuned is

A wire of length 1m is stretched by a force of 10N. The area of cross-section of the wire is 2 × 10^(–6) m^(2) and Y is 2 xx 10^(11) N//m^(2) . Increase in length of the wire will be -

A wire of length l = 3m and area of cross section 10^(-2) cm^2 and breaking stress 4.8xx10^(-7) N/m^2 is attached with block of mass 10kg. Find the maximum possible value of angular velocity with which block can be moved in circle with string fixed at one end.

A body of mass m = 10 kg is attached to a wire of length 0.3m. The maximum angular velocity with which it can be rotated in a horizontal circle is (Given, breaking stress of wire = 4.8 xx 10^(7) Nm^(-2) and area of cross-section of a wire = 10^(-2) m^(2) )

A body of mass m = 0 kg is attached to a wire of length 0.3 m. Calculate the maximum angular velcoity with wicch it can be rotated in a horizontal circle (Breaking stress of wire = 4.8 x 10^(7)N//m^(2) and area of cross-section of wire = 10^(-6)m^(2) )

For steel the breaking stressis 6xx10^(6)N//m^(2) and the density is 8xx10^(3)kg//m^(3) . The maximum length of steel wire, which can be suspended witout breaking under its own weight is [g=10m//s^(2)]