Home
Class 11
PHYSICS
A mass m is suspended from a wire . Chan...

A mass `m` is suspended from a wire . Change in length of the wire is `Deltal`. Now the same wire is stretched to double its length and the same mass is suspended from the wire. The change in length in this case will become (it is suspended that elongation in the wire is within the proportional limit)

A

`Deltal`

B

`2Deltal`

C

`4Deltal`

D

`8Deltal`

Text Solution

Verified by Experts

The correct Answer is:
C
` Deltal = (Fl)/(AY) = (Fl)/((V//l)Y) `
` = (Fl^(2))/(VY)`
`:. Deltal prop l^(2)` (as F , V and Y = constants )
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY

    DC PANDEY|Exercise Level 2 More Than One Correct|8 Videos

  • ELASTICITY

    DC PANDEY|Exercise Level 2 Comprehension Based|6 Videos

  • ELASTICITY

    DC PANDEY|Exercise Level 1 Subjective|8 Videos

  • CURRENT ELECTRICITY

    DC PANDEY|Exercise All Questions|434 Videos

  • ELECTROSTATICS

    DC PANDEY|Exercise Integer|17 Videos

Similar Questions

Explore conceptually related problems

When a wire is stretched to double its length, then

A wire is stretched to double its length. The strain is

If a wire is stretched to its length, then

A given wire is stretched to double its length. How will its resistance change ?

The resistance of a wire is 2 Omega . The wire is stretched to doubel its length. Now the resistance of the wire will become

A mass of 0.5 kg is suspended from wiere, then length of wire increase by 3 mm then work done

If a wire of resistance 1Omega is stretched to double its length, then the resistnance will become

The resistance of a wire R Omega . The wire is stretched to double its length keeping volume constant. Now, the resistance of the wire will become

The resistance of a wire of length l and diameter d is R . The wire is stretched to double its length. The resistance of the wire will now be

Increase in length of a wire is 1 mm when suspended by a weight. If the same weight is suspended on a wire of double its length and double its radius, the increase in length will be