Home
Class 11
PHYSICS
A cubical closed vessel of side 5m fille...

A cubical closed vessel of side 5m filled with a liquid is accelerated with an acceleration a. Find the value of a so that pressure at mid point` M` of `AC` is equal to pressure at `N`.
.

A

`g`

B

`2g`

C

`g/2`

D

`zero`

Text Solution

Verified by Experts

The correct Answer is:
B

`p_(N)+rho_(g)h-rho a((h)/(2))=p_(M)`
But `p_(N)=p_(M)`
`:. a=2g`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • FLUID MECHANICS

    DC PANDEY|Exercise Exercise16.3|4 Videos
  • FLUID MECHANICS

    DC PANDEY|Exercise Exercise16.4|4 Videos
  • FLUID MECHANICS

    DC PANDEY|Exercise Introductory Exercise|1 Videos
  • EXPERIMENTS

    DC PANDEY|Exercise Subjective|15 Videos
  • GENERAL PHYSICS

    DC PANDEY|Exercise INTEGER_TYPE|2 Videos

Similar Questions

Explore conceptually related problems

Figure shows an L -shaped tube tilled with a liquid to a height H . What should be the horizontal acceleration a of the tube so that the pressure at the point A becomes atmospheric.

A small ball of volume V and density rho is held inside a cubical container of side L filled with an ideal liquid of density 4 rho as .Now if the container started moving with constant acceleration a and the ball it hits the top corner point Q of the container . Then find the value of k . Given g = 10 m//s^(2)

Knowledge Check

  • A closed rectangular vessel completely filled with a liquid of density rho moves with an acceleration a =g. The value of the pressrure difference at point A and B i.e., (P_1 -P_2) is :

    A
    `rhog(b-h)`
    B
    `rhogh//2`
    C
    `rhogh`
    D
    `(rhog(b+h))/(2)`
  • A closed rectangular tank is completely filled with water and is accelerated horizontally with an acceleration towards the righ. Pressure is i. maximum and ii. minimum at

    A
    i. B ii D
    B
    i C ii D
    C
    i B ii C
    D
    i B ii A
  • A small block of wood of specific gravity 0.5 is subnerged at a depth of 1.2 m in a vessel filled with water. The vessel is accelerated upwards with an acceleration a_(0) = (g)/(2) . Time taken by the block to reach the surface, if it is released with zero initial velocity is (g = 10 m//s^(2))

    A
    0.6 s
    B
    0.4 s
    C
    1.2 s
    D
    1 s
  • Similar Questions

    Explore conceptually related problems

    A small spherical ball of density same as that of liquid is released from rest a vessel filled completely with a liquid and accelerating with acceleration 5hati+5hatjm//s as shown in the figure. Find the initial acceleration of ball just after the release with respect to vessel.

    A cubical contaienr of side length L is filled completely with water. The container is closed. It is acclerated horizontally with acceleration a. Density of water is rho . (a) Assuming pressure at point 1 (upper right corner) to be zero, find pressure at point 2 (upper left corner). (b) Pressure at point 4, at a distance h vertically below point 2 , is same as pressure at lower right corner 3. find h.

    A closed tank filled with water is mounted on a cart. The cart moves with an acceleration 'a' on a plane plane road. What is the difference in pressure between point B and A shown in figure

    If the container filled with liquid gets accelerated horizontally or vertically, pressure in liquid gets changed. In liquid ( a_(y) ) for calculation of pressure, effective g is used. A closed box horizontal base 6 m by 6 m and a height 2m is half filled with liquid. It is given a constant horizontal acceleration g//2 and vertical downward acceleration g//2 . Water pressure at the bottomof centre of the box is equal to (atmospheric pressure =10^(5)N//m^(2) density of water =1000 kg//m^(3),g=10m//s^(2) )

    For the L -shaped vessel shown in the figure, determine the value of acceleration a so that pressure at point A becomes equal to p_(0)/2 ? ( p_(0) is the atmospheric pressure)