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A mecury drop of radius 1 cm is sprayed ...

A mecury drop of radius 1 cm is sprayed into `10^(5)` droplets of equal size. Calculate the increase in surface energy if surface tension of mercury is `35xx10^(-3)N//m`.

Text Solution

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The correct Answer is:
A, C, D
`(4)/(3) pi R^(3)=10^(6)((4)/(3) pi r^(3))`
`implies r=(10^(-2))R=10^(-2)cm`
`A_(i)=4piR^(2)`
`A_(f)=(10^(6))(4 pi r^(2))`
`Delta A =A_(f)-A_(i)`
`:. Delta U =(T)(Delta A)`.
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