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Two soap bubbles in vacuum of radius 3cm...

Two soap bubbles in vacuum of radius `3cm` and` 4cm` coalesce to form a single bubble, in same temperature. What will be the radius of the new bubble?

A

`7cm`

B

`(12)/(7) cm`

C

`12cm`

D

`5cm`

Text Solution

Verified by Experts

The correct Answer is:
D
`n=n_(1)+n_(2)`
` (pV)/(RT)=(p_(1)V_(1))/(RT)+(p_(2)V_(2))/(RT)`
or, `pV=p_(1)v_(1)+p_(2)v_(2)`
`:. ((4t)/(r ))(4/3 pir^(3))=((4t)/(r_(1) ))(4/3 pir_(1)^(3))`
`+((4t)/(r_(2)))(4/3 pir_(2)^(3))`
`:. r=sqrt(r_(1)^(2)+r_(2)^2)`
`=5cm`.
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Knowledge Check

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