Two unequal soap bubbles are formed one on each side of a tube closed in the middle by a tap. What happens when the tap is opened to put the two bubbles in communication?

Options

A. No air passes in any direction as the pressures are the same on two sides of the tap
B. Larger bubble shrinks and smaller bubble increases in size till they bexome equal in size
C. Smaller bubble gradually collapses and the bigger one increases in size
D. None of the above

Answer

C

Explanation

Pressure inside a soap bubble is given by,
`P=P_(0)+(4T)/(r)` ltbRgt So, pressure inside a smaller soap bubble will be more and air will flow from smaller drop to bigger drop.