A capillary tube of radius R is immersed in water and water rises in it to a height H . Mass of water in the capillary tube is . M If the radius of the tube is doubled, mass of water that will rise in the capillary tube will now be

Options

A. `2M`
B. `M`
C. `(M)/(2)`
D. `4M`

Answer

A

Explanation

`h=(2T costheta )/(Rrhog)` or, `h prop (1)/(R)`
Now, `M=(pi R^(2)h)rho`
or, `M propR^(2)h`
or, `MpropR`
ardius is doubled, so mass in the capollary tube will also become two times.