A metal ball weighs `0.096N`.When suspended in water it has an apparent weight of `0.071N`. Find the density of the metal.

Answer

C, D

Explanation

Relative density of metal in this case is given by
`RD=("weight in air")/("change in weight in water")`
`=(0.096)/(0.096-0.071)=3.84`
`:.` Density of metal `=3.84rho_(w)`
`=3840 kg//m^(3)`.