A tank contains water on top of mercury . A cube of iron, 60mm along each edge, is sitting upright in equilibrium in the liquids. Find how much of it is in each liquid. The densities of iron and mercury are `7.7xx10^(3)kg//m^(3)` and `13.6xx10^(3) kg//m^(3)` respectively

Answer

A, B, C, D

Explanation

Let `(x) mm` is in water and `(60-x) mm` is in mercury. Total upthrust=weight
`=(0.06)^(2)(x xx10^(-3))(10^3)g+(0.06)^(2)`
`(60-x)(10^(-3))(13.6xx10^(3))g`
`=(0.60)^(3)(7.7xx10^(-3))(g)`
Solving this equation , we get
`x=28 mm` and `60-x=32mm`.