A area of cross section of a large tank is `0.5m^2`. It has an opening near the bottom having area of cross section `1cm^2`. A load of 20 kg is applied on the water at the top. Find the velocity of the water coming out of the opening at the time when the height of water level is 50 cm above the bottom. Take `g=10ms^-2`

Answer

B, C

Explanation

`((mg)/(A))+rhogh=1/2rho v^(2)`
`v=sqrt((2Mg)/(rhoA)+2gh)`
`sqrt((2xx20xx10)/(0.5 xx10^(3))+2xx10xx0.5)`
`=3.28m//s` .