What is the pressure drop (in mm Hg) in the blood as it passes through a capillary `1mm` long and `2mu m` in radius if the speed of the blood through the centre of the capillary is `0.66mm/s`? (The viscosity of whole blood is `4xx10^(-3) PI)`

Answer

A

Explanation

`v_(max)=((p_(1)-p_(2))R^(2))/(4 eta L)`
`:. (p_(1)-p_(2))=(4 eta Lv_(max))/(R^(2))`
`=((4xx4xx10^(-3))(10^(-3))(0.66xx10^(-3)))/(2xx10^(-6))^(2)`
`h=(2.64xx10^(3))/(rhog)`
`=(2.64xx10^(3))/(13.6xx10^(3)xx9.81)m of Hg`
`=0.0195m of Hg`
`~~19.5 mm of Hg`.