A liquid of specific gravity `1.5` is observed to rise `3.0 cm` in a capillary tube of diameter `0.50 mm` and the liquid wets the surface of the tube. Calculate the excess pressure inside a spherical bubble of `1.0 cm` diameter blown from the same liquid.

Answer

B, C, D

Explanation

The surface tension of the liquid is `T=(rhrhog)/(2)`
`=((0.025cm)(3.0cm)(1.5gm//cm^(3))(980cm//s^(2)))/(2)`
`=55"dyne"//cm`
Hence, excess pressure inside spherical bubble
`p=(4T)/(R)=(4xx55dyne//cm)/((0.5cm))`
`=440"dyne"//cm^(2)`