Thre is an air bubble of radius .0 mm in a liquid of surface tension `0.075Nm^-1` and density `1000 kg m^-3`. The bubble is at a depth of 10 cm below the free surface. By than the atmospheric presure? Take `g=9.8ms^-2`.

Answer

A, C

Explanation

Pressure inside the bubble `=p_(0)+rho gh+(2T)/(r)`
`:.` Amount of pressure inside the bubble greater than the atmospheric pressure `=rhogh=(2T)/(R)`
Substituting the value we get,
`Delta p=10^(3)xx9.8xx0.1+(2xx0.075)/(10^(-3))`
`=980+150=1130N//m^(2)`