If the radius and surface tension of a spherical soap bubble are 'R' and 'T' respectively, Then show that the charge required to double its radius would be `8piR ,[epsilon_(0)R[7p_(0)R+12T]]^(1/2)`. Where `p_(0)` is the atmospheric pressure.

Answer

A

Explanation

`p_(1)V_(1)=p_(2)V_(2)`
`:. (p_(0)+(4T)/(R )) ((4)/(3) pi R^(3))=(p_(0)+(4T)/(2R)-(sigma^(2))/(2 epsilon_(0))) ((4)/(3) pi)(2R)^(3)`
Here, `sigma=(q)/(A)=(q)/(4 pi (2R)^(2))`.