For the wave shown in figure, write the equation of this wave if its position is shown at `t= 0`. Speed of wave is `v = 300m//s`.
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A, B, C
The amplitude `A= 0.06 m` `:. (5)/(2)lambda = 0.2 m` `lambda= 0.08 m` `f = (v)/(lambda)=(300)/(0.08) = 3750 Hz` `k = (pi)/(lambda) = 78.5 m^(-1)` and `omega =2pif = 23562 rad//s` At `t = 0`,`x = 0 , (dely)/(delx) = "positive"` and the given curve is a sine curve. Hence, equation of wave travelling in positive x-direction should have the form, `y(x, t) = A sin(kx - omegat)` Substituting the values, we have `y(x, t) = (0.06 m) sin [(78.5 m^(-1) x = (23562 s^(-1)) t] m`
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