For the wave `y=5 sin 30pi[t-(x//240)]`, where `x and y` are in cm and `t` is in seconds, find the
(a) displacement when `t = 0` and `x = 2 cm`
(b) wavelength
( c ) velocity of the wave and
(d) frequency of the wave

Answer

A, B, C, D

Explanation

(a) Put `t =0, x = 2cm`
(b) `lambda =(2pi)/(k) = (2pi)/((30pi//240)) = 16 cm`
(c) Wave velocity `= ("Coefficient of t")/("Coefficient of x")`
`=(1)/(1//240)`
`=240 cm//s`
(d) `f =(omega)/(2pi) = (30pi)/(2pi) =15 Hz`