The speed of propagation of a wave in a medium is `300m//s`. The equation of motion of point at `x = 0` is given by `y = 0.04 sin 600 pit(metre)`. The displacement of a point `x=75cm` at `t=0.01 s` is

Options

A. `0.02 m`
B. `0.04 m`
C. zero
D. `0.028 m`

Answer

B

Explanation

`:' v = (omega)/(k)`
`:. k =(omega)/(v) = (600pi)/(300)`
`=2pi m^(-1)`
`:. y=0.04 sin(600pit - 2pix)`
Now, put `t=0.01 s` and `x =0.75m`