Home
Class 11
PHYSICS
A wave pulse is travelling on a string w...

A wave pulse is travelling on a string with a speed v towards the positive X-axis. The shape of the string at t = 0 is given by `g(x) = A sin(x /a)`, where A and a are constants. (a) What are the dimensions of A and a ? (b) Write the equation of the wave for a general time 1, if the wave speed is v.

Text Solution

Verified by Experts

The correct Answer is:
A, B
(a) Diamensions of `A and Y` are same. Similarly, diamensions of `a and x` are same.
(b) As the wave is travelling towards positive x-axis, there should be negative sign between term of `x` and term of `t`.
Further, speed of wave
`v=("Coefficient of t")/("Coefficient of x")`
`:.` Coefficient of `t = (v) xx` coefficient of `x`
Promotional Banner

Topper's Solved these Questions

  • WAVE MOTION

    DC PANDEY|Exercise Subjective Questions|2 Videos

  • WAVE MOTION

    DC PANDEY|Exercise JEE MAINS|50 Videos

  • WAVE MOTION

    DC PANDEY|Exercise Level 2 More Than One Correct|6 Videos

  • VECTORS

    DC PANDEY|Exercise Medical enrances gallery|9 Videos

  • WORK, ENERGY & POWER

    DC PANDEY|Exercise Level 2 Comprehension Based|2 Videos

Similar Questions

Explore conceptually related problems

A wave propagates in a string in the positive x-direction with velocity v. The shape of the string at t=t_0 is given by f(x,t_0)=A sin ((x^2)/(a^2)) . Then the wave equation at any instant t is given by

A wave pulse is travelling on a string at 2m//s along positive x-directrion. Displacement y of the particle at x = 0 at any time t is given by y = (2)/(t^(2) + 1) Find Shape of the pulse at t = 0 and t = 1s.

The position x of a particle at time t is given by x=(V_(0))/(a)(1-e^(-at)) , where V_(0) is constant and a gt 0 . The dimensions of V_(0) and a are

A wave pulse on a string on a string has the dimension shown in figure. The wave speed is v=1 cm /s . If point O is a free end. The shape of wave at time t = 3s si

The equation of a transverse wave travelling in a rope is given by y = 5 sin (4t - 0.02 x) , where y and x are in cm and time t is in second. Then the maximum transverse speed of wave in the rope is