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A massless rod of length L is suspened b...

A massless rod of length `L` is suspened by two identical string `AB` and `CD` of equal length. A block of mass `m` is suspended from point `O` such that `BO` is equal to 'x'. Further it is observed that the frequency of `1st` harmonic in `AB` is equal to `2nd` harmonic frequency in `CD`. 'x' is

Text Solution

Verified by Experts

The correct Answer is:
A
`f prop v prop sqrtT rArr f_(AB) =2f_(CD)`
`:. T_(AB) =4T_(CD)`
Further, `Sigma tau_p = 0 `
`:. T_(AB)(x) = T_(CD) (l-x)`
or `4x = l-x`
or ` x=l//5`
:. The correct option is (a).
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