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The period of oscillations of a point is...

The period of oscillations of a point is 0.04 s and the velocity of propagation of oscillation is 300 `m//s`. The difference of phases between the oscillations of two points at distance 10 m and 16 m respectively from the source of oscillations is

A

`2pi`

B

`pi/2`

C

`pi/4`

D

`pi`

Text Solution

Verified by Experts

The correct Answer is:
D
`:. Deltaphi = ((2pi)/lambda) (Deltax)`
`=((2pi)/(v//f))(Deltax)= ((2pi)/(vT))(Deltax)`
`= ((2pi)/(300 xx 0.04)) (16-10)`
`=pi`.
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