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Find the fundamental frequency and the next three frequencies that could cause a standing wave pattern on a string that is 30.0 m long, has a mass per unit length of `9.00 xx 10^(-3) kg//m` and is stretched to a tension of 20.0 N.

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The correct Answer is:
A, B, C, D
`v= sqrtT/mu = sqrt (20/(9xx (10^-3))) = 47.14 m//s`
`f_1 = v/(2l) = (47.14)/(2xx 30)`
= 0.786 Hz.
Next three frequencies are `2f_1, 3f_1 and 4f_1` .
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