A 60.0 cm guitar string under a tension of 50.0 N has a mass per unit length of 0.100 `g//cm.` What is the highest resonance frequency of the string that can be heard by a person able to hear frequencies upto 20000 Hz?

Answer

A

Explanation

Fundamental frequency,
`f= v/(2l) = sqrt(T//mu)/(2l)`
`= sqrt((50)//(0.1 xx 10^-3//10^-2)/(2 xx 0.6)`
` = 58.96 Hz`
Let, n th harmonic is the hightest frequency, then
(58.93)n = 20000
`:. N= 339.38`
Hence, 339 is the highest frequency.
`:. f_(max) = (339)(58.93) Hz = 19977 Hz.`