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For a person with normal hearing, the fa...

For a person with normal hearing, the faintest sound that can be at a frequency of `400 Hz` has pressure amplitude of about `6.0 xx 10^(-5)` Pa . Calculate the corresponding intensity in `W//m^(2)` . Take speed of sound in air as `344 m//s` and density of air `1.2 kg//m^(3)` .

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
:. `I = (nu(Deltap)^2m)/(2mB)`
subsituting `B = rho nu^(2)` , the about equation reduces to
`I = ((Delta p)^(2)m)/(2rho nu)=(6.0xx10^(_5))/(2xx1.2xx 344)`
`= 4.4 xx10 ^(-12) W//m^(2)`
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