Home
Class 11
PHYSICS
A tube 1.0 m long is closed at one end. ...

A tube `1.0 m` long is closed at one end. A stretched wire is placed near the open end. The wire is `0.3 m` long and a mass of `0.01 kg` . It is held fixed at both ends and vibrates in its fundamental mode. It sets the air column in the tube into vibration at its fundamental frequency by resonance. Find
(a) the frequency of oscillation of the air column and
(b) the tension in the wire.
Speed of sound in air = `330 m//s` .

Text Solution

Verified by Experts

The correct Answer is:
A, B
(a) fundamental frequency of closed pipe = `(upsilon)/ (4l)`
= `(330)/ (4xx1) = 82.5 H_(Z)`
At resonance, give that :
fundamental frequency of stretched wire (at both ends)
= fundamental frequency of air column
`:. (upsilon) / (2l) = 82.5 H_(Z)`
`:. sqrt((T//mu))/(2l)= 82.5 H_(Z)`
or `T= mu (2xx 0.3xx82.5)^(2)`
= `((0.01)/(0.3))(2xx0.3xx82.67.5)^(2)`
= `81.675 N`
Promotional Banner

Topper's Solved these Questions

  • SOUND WAVES

    DC PANDEY|Exercise Level 1 Assertion And Reason|10 Videos

  • SOUND WAVES

    DC PANDEY|Exercise Level 1 Objective|34 Videos

  • SOUND WAVES

    DC PANDEY|Exercise TYPE 5.|2 Videos

  • SOLVD PAPERS 2017 NEET, AIIMS & JIPMER

    DC PANDEY|Exercise Solved paper 2018(JIPMER)|38 Videos

  • SUPERPOSITION OF WAVES

    DC PANDEY|Exercise Level 2 Subjective|8 Videos

Similar Questions

Explore conceptually related problems

A 30.0-cm-long wire having a mass of 10.0 g is fixed at the two ends and is vibrated in its fundamental mode.A 50.0-cm-long closed organ pipe, placed with its open end near the wire, is set up into resonance in its fundamental mode by the vibrating wire. Find the tension in the wire. Speed of sound in air = 340 m s^-1 .

A steel piano wire 0.5 m long has a total mass of 0.01 kg and is stretched with a tension of 800 N. The frequency, when it vibrates in its fundamental mode, is

A steel wire 0.5 m long has a total mass of 0.02 kg and is stretched with a tension of 800N . The frequency when it vibrates in its fundamental mode is

A wire of length 40 cm which has a mass of 4 g oscillates in its second harmonic and sets the air column in the tube to vibrations in its funrations in its fundamental mode as shows in figure. Assuming the speed of sound in air as 340 m//s . Find the tension in the wire.

Consider the situation shown in figure. The wire which has a mass of 4.00 g oscillates in its second harmonic and sets the air column in the tube into vibrations in its fundamental mode. Assuming that the speed of sound in air is 40 m s^-1 , find the tension in the wire. .

In fundamental mode, the time required for the sound wave to reach upto the closed end of a pipe filled with air is 0.01 s . The frequency of vibration of air column is

Find the fundamental frequency and the frequency of the third overtone of a pipe 45 cm long. If the pipe is open at both ends (use V=344m//s )

A tube 1.0 m long is closed at one end. A wire of length 0.3 m and mass 1 xx 10^(-2) kg is streched between two fixed ends and is placed near the open end. When the wire is plucked at its mid point the air column resonates in its 1st overtone. Find the tension in the wire if it vibrates in its fundamental mode. [V_(" sound ")= 330 m"/"s] .

To decrease the fundamental frequency of a stretched string fixed at both ends one might