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What is the amplitude of motion for the air in the path of a `60 dB` , `800 H_(Z)` sound wave? Assume that `rho_(air)= 1.29 kg//m^(3)` and `upsilon = 330 m//s`.

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The correct Answer is:
A, C
`L = 10log_(10)((I)/(I_(o)))`
`60 = 10 log_(10) (I//10^(-12))`
Solving, we get `I = 10^(-6) W//m^(2)` Now, using the result derived in above problem. `A = sqrt((2l)/(rho (2 pi f )^(2)nu))`
`= sqrt((2 xx10^(-6))/(1.29 (2pi xx800)^(2)(330)))`
`= 1.36 xx10^(-8) m`
`= 13.6 nm`
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