A closed organ pipe is sounded near a guitar, causing one of the string to vibrate with large ampulitude . We vary the tension of the string until we find the maximum amplitude. The string is `80%` aas long as the closed pipe. If both the pipe and the string vibrate at their fundamental frequency, calculate the ratio of the wave speed on the string to the speed of sound in air. s

Answer

D

Explanation

`(nu)/(2(0.81)) = (nu_(2))/(4l) rArr (nu_(1))/(nu_(2)) = 0.4`