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A railroad train is travelling at 30.0 m...

A railroad train is travelling at `30.0 m//s` in still air. The frequency of the note emitted by the train whistle is `262 H_(Z)` . What frequency is heard by a passenger on a train moving in the opposite direction to the first at `18.0 m//s` and (a) approaching the first? (b) receding from the first? Speed of sound in air = `340 m//s` .

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The correct Answer is:
A, B, C
(a) `f' = f((nu + nu_(o))/(nu - nu_(s)))`
`= 262 ((340 + 18)/(340 - 30))`
`= 302 H_(Z)` (b) `f' = f((nu - nu_(o))/(nu + nu_(s)))`
`= 262 ((340 - 18)/(340 - 30)) = 228 H_(Z)`
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