A source of sound emitting waves at `360 H_(Z)` is placed in front of a vertical wall, at a distance `2 m` from it. A detector is also placed in front of the wall at the same distance from it. Find the minimum distance between the source and the detestor for which the detector detects a maximum of sound. Take speed of sound in air`= 360 m//s`. Assume that there is not phase change in reflected wave.

Explanation

`SOD - SD = lambda`
where, `lambda = (nu)/(f) = (360)/(360) = 1m`
:. `2sqrt ((x_(2))/(4) + (2)^(2)) - x = lambda =1`
Solving this equacation, we get
`x = 7.5 m`