A piano wire `A` vibrates at a fundamental frequency of `600 H_(Z)`. A second identical wire `B` produces `6` beats per second with it when the tension in `A` is slightly increased. Find the ratio of the tension in `A` to the tension in `B`.

Explanation

when `T_(A)` is increased, `f_(A)` will increase. So, it will
become `(600 + 6) = 606 H_(Z)`
Now, `f prop sqrt(T)`
`:. (T_(A))/(T_(B)) = ((f_(A))/(f_(B)))^(2) = ((606)/(600))^(2)`
`= 1.02`