For a certain organ pipe, three successive resonance frequencies are observer at `425`, `595` and `765 H_(Z)` respectively. Taking the speed of sound in air to be `340 m//s`, (a) explain whether the pipe is closed at one or open at boyh ends. (b) determine the fundamental frequency and length of the pipe.

Explanation

(a) The given frequencies are the ratio `5: 7: 9`. As the frequencies are odd multiple of `85 H_(Z)`, the pipe must be closed at one end.(b) Now, the fundamebtal frequency is the lowest, i.e.`85 H_(Z)`. ltbr. :. `85 = (nu)/(4l)`
rArr `l = (340)/(4 xx85) = 1m`